Question

Please tell the answer for 22nd question

Answer 1

Answer:

Total initial graviton potential energy $= 3 \times \frac{Gmm}{l} = \frac{3G {m}^{2} }{l}$

When length is doubled energy

$= \frac{3G {m}^{2} }{2l}$

Work done wil be change in potential energy so

$\frac{3G {m}^{2} }{l} - \frac{3G {m}^{2} }{2l} = \frac{3G {m}^{2} }{2l}$

Option 3

Answer 2

Answer:

Your answer is option 3    3Gm^2/2L

Explanation:

We have

Initial potential energy Ui=     −3Gm^2/L

Final potential energy Uf=       −3Gm^2/2L      ( new L = 2L)

W=Uf−Ui=−3Gm^2/2L−(−3Gm^2/L)   =   3Gm^2/2L

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