Question

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Answer 1

Given :-

• Mass = 1 kg
• Force applied = 6N
• Distance covered = 12 m
• Initial velocity = 0 m/s

To Find :-

• Time taken by the object to cover 12m

Formula used :-

• F = mass x acceleration
• s = ut + 1/2 at²

Solution :-

We know that,

F = mass x acceleration

Therefore,

$= > 6N = 1kg \: \times x \\ = > x = \frac{6}{1} = 6m/ {s}^{2}$

Now, for time taken,

Using second equation of motion,

$s = ut + \frac{1}{2} a {t}^{2}$

Putting the values we get,

$= > 12 = 0 \times t + \frac{1}{2} \times 6 \times {t}^{2} \\ = > 12 = 3{t}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > {t}^{2} = \frac{12}{3} = 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > t = \sqrt{4} = 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Therefore the time taken by the object to cover 12m = 2 second.

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Answer 2

Answer:

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