Please tell the answer i will do brainliest
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Let 2^x = 5^y = 10^z = k(Some constant value).
= > 2^x = k
2 = k^(1/x) ----- (1)
= > 5^y = k
5 = k^(1/y) ----- (2)
= > 10^z = k
10 = k^(1/z) ------ (3)
On solving (1) & (2), we get
= > 2 * 5 = k^(1/x) * k^(1/y)
= > 10 = k^(1/x + 1/y)
= > k^(1/z) = k^(1/x + 1/y)
Therefore 1/x + 1/y = 1/z.
Hope this helps!
= > 2^x = k
2 = k^(1/x) ----- (1)
= > 5^y = k
5 = k^(1/y) ----- (2)
= > 10^z = k
10 = k^(1/z) ------ (3)
On solving (1) & (2), we get
= > 2 * 5 = k^(1/x) * k^(1/y)
= > 10 = k^(1/x + 1/y)
= > k^(1/z) = k^(1/x + 1/y)
Therefore 1/x + 1/y = 1/z.
Hope this helps!
siddhartharao77:
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thanks yaar
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i have asked another question can u answer it please
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i have asked another question can u answer it please
i have asked another question can u answer it please
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HEYA!!!
Your answer is in the attachment....
HOPE IT HELPS!!!
Your answer is in the attachment....
HOPE IT HELPS!!!
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