please tell the answer I will mark the brainliest answer.... it's a question of maths
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Answer:
the distance of AB from centre is 4cm
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Explanation:
Let O be the centre of the circle of radius.
From O draw OD ⊥AB.
Then OD is the required distance.
∴ AD = DB = 2.5 cm (perp. from centre bisects chord) ∴ In rt. ∠d ∆ODB.
OD2 = OB2 – DB2 (Pythagoras Th.)
= (5)2 – (3)2
= 25– 9
= 16
∴ OD = √16 cm
OD = 4 cm
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