Please tell the answer of 6th question
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-i
the simplest method to solve is by using product of roots formula which is c/a
'c' is 2-i
'a' is i
and we also know one root is 2-i
Let the the other root be t
from formula t×(2-i)=2-i/I
2-i cancels on both side so t is 1/I
which can be written as -i
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im fine aap kaha se ho...
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