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Q7.
In triangle MPR AND MQR
MP=MQ(GIVEN)
/_ PMR=/_QMR (MR IS THE BISECTOR OF /_PMQ)
MR=MR(COMMON)
SINCE TRIANGLE MPR CONGRUENCE TO MQR
PROVED
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6) Here,
(ii)AB||CD
IN TRIANGLE AOB and COD,
AB=CD (given)
_OAB=_ODC
_OCD=_OBA
Hence by ASA congruence criterion
∆AOB congruent to ∆ COD
(ii) AO=OD (proved above)
Hence
AO = 1/2 OD
(iii) Similarly,
BC=2OC
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