please tell the answer of my question
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Let CD⊥AB. Then, CD=p
∴ Area of ΔABC=
2
1
(Base×Height)
=
2
1
(AB×CD)=
2
1
cp
Also,
Area of ΔABC=
2
1
(BC×AC)=
2
1
ab
∴
2
1
cp=
2
1
ab
⇒cp=ab
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