Please tell the answer of question 40.
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Hope this answer will help u and please mark BRAINLIEST.
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The perpendicular drawn from the centre of the circle to a chord bisect the chord.
AP = BP
CQ = DQ
By Pythagoras Theorm.
OB^2 = BP^2 + PO^2
OP^2 = BO^2 - BP^2
= 5^2 - 4^2
= 25 - 16
OP^2 = 9
OP = ROOT 9
OP = 3
Similarly
OQ^2 = 5^2 - 3^2
= 25 - 9
= 16
OQ = ROOT 16
OQ = 4
PQ = PO + QO
= 3 + 4
= 7
THEREFORE PQ = 7CM
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