Math, asked by redmi123, 1 month ago

please tell the answer of question no 21​

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Answered by KingSrikar
4

Given Data :

  • Area of Trapezium Shaped Field = 480 cm²
  • Distance Between Two Parallel Sides = 15 m
  • One of the Parallel Side = 20 m

To Find : Measure of Other Parallel Side in the Trapezium

Answer : Measure of Other Parallel Side = 44 m

Step By Step Solution :

➤ Let Other Parallel Side be x

  • Area of Trapezium Shaped Field = 480 cm²
  • 1/2 × Sum of Parallel Sides × Distance Between Them = 480 m²
  • 1/2 × Sum of Parallel Sides × 15 m = 480 m²
  • 1/2 × (20 m + x) × 15 m = 480 m²
  • [1/2 × (20 m + x) × 15 m]/15 m = 480 m²/15 m
  • 1/2 × (20 m + x) = 32 m
  • 1/2 × (20 m) + 1/2 × (x) = 32 m
  • 10 m + (x/2) = 32 m
  • x/2 = 32 m - 10 m ⇒ x/2 = 22 m ⇒ x = 22 × 2 m ⇒ x = 44 m
Answered by pratham7777775
8

Step-by-step explanation:

Area of Trapezium Shaped Field

480 cm

Distance Between Two Parallel

Sides 15 m

One of the Parallel Side = 20 m

To Find : Measure of Other Parallel Side

in the Trapezium

Answer: Measure of Other Parallel Side

44 m

Step By Step Solution:

>Let Other Paralel Side be x

.Area of Trapezium Shaped Field =

480 cm

.1/2 x Sum of Parallel Sidesx

Distance Between Them = 480 ms

1/2 x Sum of Parallel Sides x 15 m =F

480 m

.1/2 x (20 m +x)x 15 m 480 m2

(1V2 x (20 mtx)*15 m]/15 m = 480

m/15 mn

.1/2 x (20 m +x) = 32 m

1/2 x (20 m) +1/2 x (x) = 32 m

10 m+ (x/2) = 32 m

>Let Other Parallel Side be x

.Area of Trapezium Shaped Field =

480 cm

.1/2 x Sum of Parallel Sides x

Distance Between Them = 480 m

.1/2 x Sum of Parallel Sides x 15 m =

480 m

1/2 x (20 m+x) x 15 m= 480 m

[1/2 x (20 m+x) * 15 m/15 m = 480

m/15 mn

.1/2 x (20 m +x)= 32 m

.1/2 x (20 m) + 1/2x (x) = 32 m

.10 m + (x/2) = 32 m

x/2 = 32 m- 10 mx/2 = 22 m X

22 * 2 m » X= 44 m

Hope it helps !!!

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