please tell the answer please
all the fourth
Answers
Answer:
i)Given figure consists of two figures, they are
right angled triangle and Trapezium
The area of the given figure is equal to the
sum of the areas of two figures
Area of A ABC :
Base = BC = 12 cm
Height = AB = 5 cm
Area of a triangle = (1/2)×bh sq.units
=> Area of A ABC = (1/2)×BCXAB
=> (1/2)×12×5 cm²
=> 60/2 cm²
=> 30 cm²
Area of A ABC = 30 cm²
-(1)
In A ABC, AB = 5 cm and BC = 12 cm
By Pythagoras theorem
AC² = AB²+BC²
=> AC² = 5²+12²
=> AC² = 25+144
=> AC² = 169
=> AC =√169
=> AC = 13 cm
Area of the TrapeziumIn A ABC, AB = 5 cm and BC = 12 cm
By Pythagoras theorem AC² = AB²+BC²
=> AC² = 5²+12²
AC² = 25+144
AC² = 169
=> AC =√169
=> AC = 13 cm
Area of the Trapezium ACDE:
Parallel sides AC = (a) = 13 cm DE = (b) = 7 cm
Distance between them =AE =(h) = 3 cm
Area of a Trapezium = (1/2)h(a+b) sq.units
Area of the Trapezium = (1/2)×AEX(AC+DE)
=> (1/2)×3(13+7) cm²
=> (1/2)×3×20 cm² => 60/2 cm²
=> 30 cm²
Area( ACDE) = 30 cm²
-(2)
Area of the given figure = Ar(AABC) +Ar(ACDE)
=> 30+30=60 cm²
Area of the given figure is 60 cm²
(b) Area of regular octagon=
Area of two trapezium+ Area of rectangle
2x1/2(a+b)h + lxb (10+22)8+ 10×22
32x8+220
256+220
476cm²
(c) Area enclosed=
Area of trapezium+ Area of square
1/2(a+b)h + s²
1/2(7+18)8 + 18²
4x25+ 324
100+324
424cm²
(d) Area of hexagon=
Area of two triangles+ Area of rectangle
2x1/2xbxh + lxb
16x6+10×16
96+160
256cm²
Step-by-step explanation:
hope it helps
256cm²is the correct answer for you