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Answer 1

Answer:

x=1

Step-by-step explanation:

$(\frac{-7}{11} )^{-3}$ x $(\frac{-7}{11} )^{5x}$=$[(\frac{-7}{11} )^{-2}]^{-1}$

When we multiply things with the same base and different exponents we add the exponents. Also, when brackets are put then the exponents get multiplied(regarding LHS)

So, $(\frac{-7}{11} )^{5x-3}$=$(\frac{-7}{11} )^{2}$

As they both are the same base we can now compare the exponents.

So, we get,

$5x-3=2\\5x=2+3\\5x=5\\x=5/5\\Therefore, x=1$