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question number 5
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Answer:
Given:
A body is dropped from the edge of a roof .
To find:
- Time taken to travel 4.9 metres
- Speed at that position
- How the body moves at 7.9 metres
- What is the acceleration after 1 second and 2second.
Calculation:
Since ball is dropped from edge, we get initial Velocity to be zero.
1. s = ut + ½gt²
=> 4.9 = 0 + ½ × (9.8) × t²
=> t = 1 second.
2. Speed at that position :
∴ v = u + gt
=> v = 0 + (9.8) × 1
=> v = 9.8 m/s
3. Speed at 7.9 metres:
∴ v² = u² + 2gh
=> v² = 0 + 2(9.8)(7.9)
=> v² = 148.96
=> v = 12.20 m/s
4. Acceleration at the end of 1 sec and 2 second will be equal to Acceleration due to gravity (i.e 9.8 m/s²)
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