Question

please tell the answer
this question from matrices​

Answer 1

Answer:

Hey mate here is your answer

Answer is A

Step-by-step explanation:

Follow me

Markasbrainlist

Give thanks

Answer 2

Answer:

A³ - 35A = A

Step-by-step explanation:

Given,

A = $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$

⇒ A = 2[2(2)-2(2)] - 2[2(2)-2(2)] + 2[2(2)-2(2)]

⇒ A = 2[0] - 2[0] + 2[0]

⇒ A = 0

A³ =  $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$  $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$  $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$

⇒ A³ = $\left[\begin{array}{ccc}2(2)&2(2)&2(2)\\2(2)&2(2)&2(2)\\2(2)&2(2)&2(2)\end{array}\right]$ $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$

⇒ A³ = $\left[\begin{array}{ccc}4&4&4\\4&4&4\\4&4&4\end{array}\right]$ $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$

⇒ A³ = $\left[\begin{array}{ccc}4(2)&4(2)&4(2)\\4(2)&4(2)&4(2)\\4(2)&4(2)&4(2)\end{array}\right]$

⇒A³ = $\left[\begin{array}{ccc}8&8&8\\8&8&8\\8&8&8\end{array}\right]$

Evaluate the value of det,

⇒ A³ = 8(8(8)-8(8)) - 8(8(8)-8(8)) + 8(8(8)-8(8))

⇒ A³ = 8(0) - 8(0) + 8(0)

⇒ A³ = 0

now, evaluate '35A'

⇒ 35A = 35 $\left[\begin{array}{c,c,c}2&2&2\\2&2&2\\2&2&2\end{array}\right]$  

⇒ 35A = 35(0) = 0

so, ∴ A³ - 35A = 0 - 0 = 0 = A

HOPE THIS WOULD BE HELPFUL FOR YOU