please tell the answer tomorrow is my exam
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using trigonometro
sin 90 = perpendicular /hypotenuse
1=AC/15
AC = 15
Now by using Pythagoras theorem.
hypotenuse ²= perpendicular ²+base²
sin 90 = perpendicular /hypotenuse
1=AC/15
AC = 15
Now by using Pythagoras theorem.
hypotenuse ²= perpendicular ²+base²
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