please tell the answers fast only 8th question
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Question :
- In ∆ABC ∠A = 2x - 5 ° , ∠B = 5x + 5° and ∠C = 3x + 50° , Find the value of x and ∠A , ∠B and ∠C.
Solution :
As we know that,
So,
⇨∠A + ∠B + ∠C = 180
⇨2x - 5 + 5x + 5 + 3x + 50 = 180
⇨ 2x + 3x + 5x + 50 + 5 - 5 = 180
⇨ 10x + 50 = 180
⇨ 10x = 180 - 50
⇨ 10x = 130
⇨ x = 130/10
⠀⠀⠀⠀⠀⠀⠀⠀ x = 13
⟶ ∠A = 2x - 5
⟶ ∠A = 2 × 13 - 5
⟶ ∠A = 26 - 5
⠀⠀⠀⠀⠀⠀⠀⠀∠A = 21°
⟶ ∠B = 5x + 5
⟶ ∠B = 5 × 13 + 5
⟶ ∠B = 65 + 5
⠀⠀⠀⠀⠀⠀⠀⠀ ∠B = 70°
⟶ ∠C = 3x + 50
⟶ ∠C = 3 × 13 + 50
⟶ ∠C = 39 + 50
⠀⠀⠀⠀⠀⠀⠀⠀ ∠C = 89°
☣️Verification :
Sum of interior angles of triangle = 180°
∠A + ∠B + ∠C = 180
21 + 70 + 89 = 180
91 + 89 = 180
180 = 180
LHS = RHS
Hence Verified
So,
- Value of x = 13
- ∠A = 21°
- ∠B = 70°
- ∠C = 89°
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