Question

Please tell the answers of all the questions it's urgent........ Thanks ​

Answer 1

Answer:

see below

Step-by-step explanation:

sin (x+ 30°) = ½

sin (x+ 30°) = sin30°

x + 30° = 30°

x = 0°

i) Cosec N = 17/15

sin N = 1/cosecN

sin N = 15/17

cosN = √ (1 - sin^2N)

Cos N = √(1 - 15×15/17×17)

Cos N = 8/17

but.....cos N = LM/LN

LM/LN = 8/17

1 - (LM/LN)^2 = 1 - (8/17)^2

LN^2 -LM^2/(LN)^2 = (15/17)^2

but....LN^2 -LM^2 = MN^2

hence MN = 15

since... tan L = MN/LM

therefore...tan L = 15/ 8

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