Math, asked by divyaaptekar33, 5 days ago

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Answered by tennetiraj86
0

Solutions:-

1)

Given that

A = 4x³+6xy

And A+X = 0

=> X = 0+(-A)

=> X = -A

=> X = -(4x³+6xy)

=> X = -4x³-6xy

The expression of X = -4x³-6xy

2)

[(5/x³)+7xy-6y³] + 0 = [(5/x³)+7xy-6y³]

0 is the additive identity element.

3)

Given that

(abc + a³+b³+c³ )+----- = 3abc+2b³

Let (abc + a³+b³+c³ )+ X = 3abc+2b³

=> X = (3abc+2b³)-(abc + a³+b³+c³ )

=> X = 3abc+2b³-abc-a³-b³-c³

=> X = (3abc-abc)+(2b³-b³)-a³-c³

=> X = 2abc+b³-a³-c³

=> X = 2abc-a³+b³-c³

Therefore,

(abc + a³+b³+c³ )+(2abc-a³+b³-c³) = 3abc+2b³

Answered by krohit68654321
0

Step-by-step explanation:

Solutions:-

1)

Given that

A = 4x³+6xy

And A+X = 0

=> X = 0+(-A)

=> X = -A

=> X = -(4x³+6xy)

=> X = -4x³-6xy

The expression of X = -4x³-6xy

2)

[(5/x³)+7xy-6y³] + 0 = [(5/x³)+7xy-6y³]

0 is the additive identity element.

3)

Given that

(abc + a³+b³+c³ )+----- = 3abc+2b³

Let (abc + a³+b³+c³ )+ X = 3abc+2b³

=> X = (3abc+2b³)-(abc + a³+b³+c³ )

=> X = 3abc+2b³-abc-a³-b³-c³

=> X = (3abc-abc)+(2b³-b³)-a³-c³

=> X = 2abc+b³-a³-c³

=> X = 2abc-a³+b³-c³

Therefore,

(abc + a³+b³+c³ )+(2abc-a³+b³-c³) = 3abc+2b³

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