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given: ln ∆ABC ,AD is perpendicular bisector of BC
To prove: ABC is a isosceles triangle in which AB=AC
proof: ln ∆ADC
angle ADB =angle ADE | Each =90°DB=DC
therefore AD=AD (common)
∆DB~= ∆ ADC ( by SAS rule)
AB=AC (cpct)
∆ABC is a isosceles triangle in which AB=AC.
hope it helps you
Answered by
3
Answer:
given: ln ∆ABC ,AD is perpendicular bisector of BC
To prove: ABC is a isosceles triangle in which AB=AC
proof: ln ∆ADC
angle ADB =angle ADE | Each =90°DB=DC
therefore AD=AD (common)
∆DB~= ∆ ADC ( by SAS rule)
AB=AC (cpct)
∆ABC is a isosceles triangle in which AB=AC.
hope it helps you
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