Please tell the following answer and explain it properly
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Given, R1= 3 ohm,R2 = 4 ohm,R3 = 2 ohm,R4 = 4 ohm,R5 = 5ohm ,and V = 3v.
By Ohm's Law,
V = I ×R
Therefore,by substituting the values,
3 = I × (R1+R2+R3+R4+R5) ( Because The resistors are connected in series,So , equivalent resistance is equal to sum of individual resistance.)
Therefore, I = (3+4+2+4+4)÷3
= (17)÷3
= 0.375 A
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heyy I'm weak in physics
sorry I can't help you....
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