please tell the full constructions I will mark brainiest
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1) draw a line segment jk=7.5cm
2)at j as centre draw an angle of 40°which forms line segment jx
3) now with K as centre draw an arc of 1.7cm(sayAk) such that it intersects the line jx at A.
Thus ΔAJK is the required triangle.
Step-by-step explanation:
the shape will be like the image for exact construction use compass and scale
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