please tell the sixth answer
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Given:- (x - 2/3y)^3
Using identity
(x-y)^3 = x^3 - y^3 - 3xy(x-y)
ATQ
x^3 - (2/3y)^3 - 3*x*2/3 (x-2/3y)
x^3 - 8/27y^3 -2x^2 + 4/3xy
Hence answered
Using identity
(x-y)^3 = x^3 - y^3 - 3xy(x-y)
ATQ
x^3 - (2/3y)^3 - 3*x*2/3 (x-2/3y)
x^3 - 8/27y^3 -2x^2 + 4/3xy
Hence answered
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Using identity
(x-y)^3 = x^3 - y^3 - 3xy(x-y)
ATQ
x^3 - (2/3y)^3 - 3*x*2/3 (x-2/3y)
x^3 - 8/27y^3 -2x^2 + 4/3xy
Hence answered