Math, asked by ash4616, 1 year ago

please tell the sixth answer

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Answers

Answered by ssj4adityasupar
0
Given:- (x - 2/3y)^3

Using identity
(x-y)^3 = x^3 - y^3 - 3xy(x-y)

ATQ
x^3 - (2/3y)^3 - 3*x*2/3 (x-2/3y)

x^3 - 8/27y^3 -2x^2 + 4/3xy

Hence answered

ssj4adityasupar: Given:- (x - 2/3y)^3

Using identity
(x-y)^3 = x^3 - y^3 - 3xy(x-y)

ATQ
x^3 - (2/3y)^3 - 3*x*2/3 (x-2/3y)

x^3 - 8/27y^3 -2x^2 + 4/3xy

Hence answered
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