Question

please tell the solution of this.....i will mark as brainliest​

Answer 1

I hope it will help you

Step-by-step explanation:

y= e^(x-y)

taking log both side we get

logY =x-y

or y=x-logy

differciating both side with respect to x

(dy/dx)= 1- (1/y)*(dy/dx)

or (dy/dx){1+(1/y)}=1

or,(dy/dx){(y+1)/y}=1

or,dy/dx={y/(1+y)}......proved