Question

please tell the solution please​

Answer 1

Answer:

A∪B = {a, b, c, d, e, f, g, h}

A∩B = {a, d, h}

A – B = {c, f}

B – A = {b, e, g}

Step-by-step explanation:

We have,

A = {a, c, d, f, h}

B = {a, b, d, e, g, h}

We know that,

A∪B is the set of elements which contains all the elements of set A and set B. It is read as

"A union B". (Common terms are not repeated)

Thus,

A∪B = {a, b, c, d, e, f, g, h}

Now,

A∩B is the set elements which contains elements common in both set A and set B. It is read as "A intersection B".

Thus,

A∩B = {a, d, h}

Now,

A – B is the set of elements that are present only in set A and not in set B. It is read as

"A minus B".

Thus,

A – B = {c, f}

Now,

B – A is the set of elements that are present only in set B but not in set A. It is read as

"B minus A".

B – A = {b, e, g}

Hope it helped and believing you understood it........All the best