Question

please tell the solutions of this question.... who gave me answer first I hit on brain list and the answer must be right..... ​

Answer 1

angel ACB=(180-100)°=80°

angel ABC=180-(80+35)°=65°

Answer 2

hope this helps u

given

∠acd=100°

∠qap=35°

solution

∠bac=∠qap(vertically opposite angles)

∠bac =35° .....(1)

∠acb+∠acd= 180 (linear pair)

∠acb=180-∠acd

        = 180-100

∠acb=80°....(2)

∠bac+∠acb∠cba=180(angle sum property of a triangle)

from (1)(2) we can say

35+80+∠cba=180

∠cba=180-115

∠cba=65°