Question

please tell the value of x, y​

Answer 1

In △QSR, we have

∠QRT = ∠RSQ + ∠SQR ....(Exterior angle of triangle is equal t sum of interior opposite angles)

⇒65° = ∠RSQ + 28°

⇒∠RSQ = 65° − 28°

⇒∠RSQ = 37°

We have,

y + ∠RSQ = 90° ....(Given)

⇒ y + 37° = 90°

⇒y = 90° − 37° = 53°

In △PQS, we have

x∘ + y∘ + ∠P = 180° ....(Angle sum property)

⇒ x + 53° + 90° = 180°

⇒x = 180° − 143° = 37°