Math, asked by unicorngirl367, 3 months ago

please tell these questions​

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Answered by Namankumarshah
0

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Step-by-step explanation:

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Answered by priyaayika
8

Answer:

Q. 14.

we know that the sum of the four angles of a quadrilateral is equal to 360° .

let us take equal angles (as mention in the question) be of x°

then.,

x + x + x + 150 = 360

3x = 360 - 150

3x = 210

x = 70

the measure of equal angles is 70

Q. 15.

let the number be x

two thirds of the number = 2x/3

according to the problem given,

x +  \frac{2x}{3}  = 55

 \frac{3x + 2x}{3}  = 55

 \frac{5x}{3}  = 55

x =  \frac{(55 \times 3)}{5}

x = 11 \times 3

x = 33

the number is 33

Q. 16.

 =  \frac{9x {}^{2} }{ \sqrt{3x} }

 =  >    \frac{3 \times  \sqrt{3} \times  \sqrt{3 \: x}  }{ \sqrt{3} }

 =  > 3 \sqrt{3x}

Q. 17.

given that

base area = 180 cm²

volume = 900 cm³

we need to find the height of cuboid.,

now,

volume of a cuboid = 900

base area × height = 900

180 × h = 900

height =  \frac{900}{180}

 \:  \:  \:  \:  =  \frac{90}{18}

height of cuboid = 5 cm

Q. 18.

for any polyhedron,

faces + vertices - edges = 2

here.,

faces = 20

vertices = 12

edges = ?

using above formula.,

20 + 12 - edges = 2

32 - edges = 2

edges = 30

Q. 19.

sample space = 1,2,3,4,5,6.

A perfect square in samples = 1,4

= 2

probability of getting perfect square

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  =  \frac{2}{6}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{1}{3}

Q. 20.

given that

here, king,queen and jack of club are removed from the deck of 52 playing cards

so, remaining cards in deck = 52-3 = 49

total number of outcomes = 49

we know that there are 4 queens in a deck.after removing a queen of club we left with 3 queens.

let

 e_{2} = event \: of \: getting \: a \: queen

number of favourable outcomes to

 e_{2} = 3

required probability

p( e_{2}) =  \frac{3}{49}

hope it's help you

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