Question

please tell this ans ​

Answer 1

Answer:

40 students

Step-by-step explanation:

let take the total students of class = x

half of the students that are playing = x/2

students went to ice-cream shop= 3/5

And students that stayed in class = 8

Now ,

X/2 + 3/5 × X/2 + 8 = X

X/2+3x/10+8=X

5x+3x+80/10 = X

8x+80=10x

80=2x

X=80/2

X= 40

Total students in the class are :- 40 Students

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Answer 2

ANSWER✔

$\large\underline\bold{ASSUMING,}$

$\sf\dashrightarrow total\:number\:of\:students\:of\:class\:be'x'$

NOW,

$\sf\dashrightarrow number\:of\:students\:playing\:on\:the\:ground\: (half\:of\:the\:class) = \dfrac{x}{2}$

$\sf\dashrightarrow number\:of\:students\:went\:in\:iecream\:shop= \dfrac{3}{5}$

$\sf\dashrightarrow student\:who\:stayed\:in\:class\:itself= 8$

$\large\underline\bold{TO\: FIND,}$

$\sf\dashrightarrow total\:number\:of\:students\:in\:the\:class.$

$\large\underline\bold{SOLUTION,}$

✯ACCORDING TO THE QUESTION,

$\sf\implies \dfrac{x}{2} + \dfrac{3}{5} \times \dfrac{x}{2} +8=x$

$\sf\implies \dfrac{x}{2} + \dfrac{3x}{10} +8=x$

$\sf\implies \dfrac{(10x+6x)}{20} +8=x$

$\sf\implies \dfrac{2(5x+3x)}{20} +8=x$

$\sf\implies \dfrac{\cancel{2}(5x+3x)}{\cancel{20}} +8=x$

$\sf\implies \dfrac{5x+3x}{10}+8=x$

$\sf\implies \dfrac{8x+80}{10}= x$

$\sf\implies \dfrac{8(x+10)}{10}= x$

$\sf\implies 8(x+10)=10x$

$\sf\implies x+10= \dfrac{10x}{8}$

$\sf\implies x+10= \dfrac{\cancel{10x}}{\cancel{8}}$

$\sf\implies x+10= \dfrac{5x}{4}$

$\sf\implies 4x+40=5x$

$\sf\implies 40= 5x-4x$

$\sf\implies 40= x$

$\large{\boxed{\bf{\star\:\: x=40\:\: \star }}}$

$\large\underline\bold{TOTAL\:NUMBER\:OF\:STUDENTS\:ARE\: 40.}$

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