Question

please tell this answer​

Answer 1

$\LARGE{\underline{\bf{Required\: Answer :}}}$

GiveN:

• Length of the rectangle = 26 m
• Breadth of the rectangle = 12 m

To FinD:

• Area of the shaded region?

Step-wise-Step Explanation:

The area of the shaded region = Total area of the rectangle - Area of the unshaded region.

Here the unshaded part comprises of two semi-circles and a rectangle.

And,

• Width of inner rectangle = 12 m - 2(4 m) = 4 m
• Length of inner rectangle = 26 m - 2(3 m) - 2(2 m) = 16 m
• Radius of semi-circle = 2 m

First finding area of rectangle:

⇒ L × B unit²

⇒ 26 m × 12 m

⇒ 312 m²

Area of the unshaded region:

• 2(Area of semi-circles) + Area of rectangle.

Let's calculate using formula,

⇒ 2(πr² / 2) + l × b unit²

⇒ π(2)² + 4 × 16 m²

⇒ 4π + 64 m²

Then, area of the shaded region:

⇒ Area of rectangle - Area of unshaded region

⇒ 312 m² - (4π + 64) m²

⇒ 312 m² - 4π - 64 m²

⇒ 248 - 4π m²

Hence,

The correct answer is 248 - 4π.

$\huge{ \boxed{ \sf{ \pink{Option \: C}}}}$

Answer 2

$\huge \green {\sf {Answer :}}$

Given:

Length of the rectangle = 26 m

Breadth of the rectangle = 12 m

To FinD:

Area of the shaded region?

Step-wise-Step Explanation:

The area of the shaded region = Total area of the rectangle - Area of the unshaded region.

Here the unshaded part comprises of two semi-circles and a rectangle.

And,

Width of inner rectangle = 12 m - 2(4 m) = 4 m

Length of inner rectangle = 26 m - 2(3 m) - 2(2 m) = 16 m

Radius of semi-circle = 2 m

First finding area of rectangle:

⇒ L × B unit²

⇒ 26 m × 12 m

⇒ 312 m²

Area of the unshaded region:

2(Area of semi-circles) + Area of rectangle.

Let's calculate using formula,

⇒ 2(πr² / 2) + l × b unit²

⇒ π(2)² + 4 × 16 m²

⇒ 4π + 64 m²

Then, area of the shaded region:

⇒ Area of rectangle - Area of unshaded region

⇒ 312 m² - (4π + 64) m²

⇒ 312 m² - 4π - 64 m²

⇒ 248 - 4π m²

Hence,

$\small \underline \red {\sf{ The \ correct \ answer \ is \ 248 - 4π. }}$