Question

please tell this answer​

Answer 1

Answer:

From conservation of energy

1/2 * m_{1} * v_{1} ^ 2 + 1/2 * m_{2} * v_{2} ^ 2 = 1/2 * m_{1} * v_{1} ^ 2 + 1/2 * m_{2} * v_{2} ^ 2

1 2 m 1 v^ 2 + 1 2 m 2 v^ 2 = 1 2 m 2 v^ prime2 ....(1)

1 2 m 1 v^ 2 - 1 2 m 2 v^ 2 = 1 2 m 2 v^ prime2

v^ prime = n(m 1 -m 2 ) m 2

Put the value of v^ prime in eq (1)

1 2 m 1 v^ 2 + 1 2 m 2 v^ 2 = 1 2 m 2 *( v(m 1 -m 2 ) m 2 ) 2

m_{1} + m_{2} = ((m_{1} - m_{2}) ^ 2)/m_{2}

m_{1}*m_{2} + m_{2} ^ 2 = m_{1} ^ 2 + m_{2} ^ 2 - 2m_{1} * m_{2}

m_{2} = m_{1}/3 ...(2)

The volume of the fiist sphere is v and volume of other is v / 3

The volume of the fiist sphere is v and the

volume of other is

v / 3

Now, the radius of the sphere is r and other sphere is r^ prime

4 3 pi r^ prime 3= v 3 ...(3)

4 3 pi r^ prime 3= v 3 ....(4)

The volume of first sphere is the volume of radius other sphere is Divide eq. (4) by (3) r^ prime = r (3) 1/2

Answer. = r/(3) 1/2