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Answers
Step-by-step explanation:
a)if John had x marbles then gomathi had 45-x marbles
b)gomathi had 40-x marbles after losing 5 marbles
c) (x-5)(40-x)=124
40x-200-x²+5x=124
45x-x²=124+200
x²-45x+324
★ Concept
This question is based on Basic Algebra where the use of Algebraic Expression, linear equation in one variable and Quadratic Equation are common.
Let's proceed with calculation !!
Given that ::
John and Gomathi are playing with marbles such that all together they have 45 marbles.
a) If John had 'x' marbles, then how many marbles Gomathi had ?
Assumption made that John had 'x' marbles and it's already mentioned in the question that together John and Gomathi had 45 marbles.
→ John marbles + Gomathi marble = 45
→ Gomathi marbles = 45 - John marbles
→ Gomathi marbles = (45 - x) marbles.
Therefore, Gomathi had (45 - x) marbles.
b) How many marbles were left with Gomathi after losing 5 ?
Furthermore, it's given that both of them lost 5 marbles ; in previous sub part we have assumed John's marbles to be 'x' and so does Gomathi marbles came out to be (45 - x). After losing 5 marbles they were left with -
>> John's marbles = (x - 5)
Gomathi marbles = [(45 - x) - 5] = (40 - x)
Therefore, after losing 5 marbles Gomathi left with (40 - x) marbles.
c) Write an equation for the product of marbles they had after losing 5 marbles each.
Provided that, after losing 5 marbles each, the product of their marbles is 124 ; Mathematically
Although in the question it's not mention to solve the equation further for 'x' (finding the number of marbles, they had originally). Here we go !! [Quadratic part using Factorisation]
Either
⋆ If (x - 9) = 0 ; x = 9
John had 9 marbles while Gomathi had (45 - 9) = 36 marbles.
⋆ If (x - 36) = 0 ; x = 36
John had 36 marbles while Gomathi had (45 - 36) = 9 marbles.