Math, asked by dineshjmindia, 1 year ago

please tell this answer with proper statements and explanation I will give you brainliest​

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Answered by asifa127
0

(x+a) is a factor of (x^n+a^n)

n is a integers number. we substitute n=1,2,3,......

x^1+a^1=we get (x+a)

X^2+a^2= it is a ^2+b^2 formula

Now You write (x+a)(x-a) =x+a is a factor of x+a and x-a. like that u simplify. finally we got x+a is a factor.

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