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(x+a) is a factor of (x^n+a^n)
n is a integers number. we substitute n=1,2,3,......
x^1+a^1=we get (x+a)
X^2+a^2= it is a ^2+b^2 formula
Now You write (x+a)(x-a) =x+a is a factor of x+a and x-a. like that u simplify. finally we got x+a is a factor.
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