Math, asked by av1266108, 11 months ago

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Answered by jjlil1804
0

Answer:

the present ages of mohit and mayank are in the ratio :8 after 8 year. the ratio of thier ages will be 5 :4 find their present ages

Answered by SavinaySingh
0

Answer:

let present age of mohit and mayank be 11x and 8x respectively

after 8 years,

mohit=11x+8

mayank=8x+8

(ATQ)

4(11x+8)=5(8x+8)

44x+32=40x+40

4x=8

x=2

present ages,

mohit = 11x=22 yrs

mayank =8x=16 yrs

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