Question

please tell this question no. 3. I will mark as brainleist.please very urgent.

Answer 1

Let the digit in ones place be x and tens place be y

Original number = 10y + x

Number formed by reversing the digits = 10x + y

Given 10y + x = 4(x + y) + 3

⇒ 10y + x − 4x − 4y = 3

6y-3x=3

2y-x=1

-x+2y=1 ___(1)

Also given that when 18 is added to the number the digits gets interchanged.

Hence (10y + x) + 18 = 10x + y

⇒ 9x − 9y = 18

x-y=2---(2)

adding (1) and (2) we get

-x + 2y= 1

x - y =2

_______

y = 3

------

substituting the value of y as 3 in any of the above equations we get x value

-x+2(3)=1

-x=-5

x=5

Hence (10y + x) = 10(3) + 5 = 35

Hope this helps you out.

Answer 2

Answer:

Step-by-step explanation:

Hello there,

Let the digit in ones place be x and tens place be y

Original number = 10y + x

Number formed by reversing the digits = 10x + y

Given 10y + x = 4(x + y) + 3

=> 10y + x − 4x − 4y = 3

=> 6y - 3x = 3

=> 2y - x = 1

=> -x + 2y = 1 -----------(1)

Also given that when 18 is added to the number the digits gets interchanged.

Hence (10y + x) + 18 = 10x + y

=> 9x − 9y = 18

=> x - y = 2 ---------(2)

adding (1) and (2) we get

=> -x + 2y = 1

=> x - y =2

=> y = 3

substituting the value of y as 3 in any of the above equations we get x value

=> -x + 2(3) = 1

=> -x = -5

=> x = 5

Hence (10y + x) = 10(3) + 5 = 35

Hope you find my answer useful.

Please refer the above answer of Yashu too.

Harith