Question

please tell this question no. 40​

Answer 1

$x^{a-b}$ = $\frac{x^{a} }{x^{b} }$

$x^{b-a}$ = $\frac{x^{b} }{x^{a} }$

1 / (1 + $\frac{x^{a} }{x^{b} }$ )= $\frac{x^{b} }{x^{a} + x^{b} }$

and

1 / (1 + $\frac{x^{b} }{x^{a} }$ ) =  $\frac{x^{a} }{x^{a} + x^{b} }$

$\frac{x^{a} }{x^{a} + x^{b} }$ +  $\frac{x^{b} }{x^{a} + x^{b} }$ =  $\frac{x^{a} + x^{b} }{x^{a} + x^{b} }$ = 1

Answer 2

Answer:given below

Step-by-step explanation:

LHS={1+x^(b-a)}+{1+x^(a-b)}/{1+x^(a-b)}{1+x^(b-a)}

=2+x^(b-a+a-b)/{1+x^(b-a)+x^(a-b)+x^(a-b+b-a)}

=2+1/{1+1+1}=3/3=1

Therefore LHS=RHS