Math, asked by ishantripathi601, 8 months ago

please tell very fast .......​

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Answered by ishanlegendspi9
1

Answer:

(3+i)²+a(3+i)+b=0

therefore solving it .

9+i²+6i+3a+3i+b=o

i²+9i+3a+b+9=0

3a=-9i-i²-b-9

a=-(9i-i²-b-9)*1/3.

hope this helped .

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