please tell very important tomorrow is my exam
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x = 3 + 2√2
1 / x = 1 / (3+2√2)
by rationalizing it
= 1 / (3+2√2) × { (3-2√2)/ (3-2√2) }
= (3-2√2) / 9 - 8
= (3-2√2)
so,
1/x = (3-2√2)
the question is
{x -(1/x)}^2
{3 + 2√2 - ( 3 - 2 √2)}^2
( 3 -3 + 2√ 2 + 2√2)^2
( 4√2)^2
16 × 2
= 32.
1 / x = 1 / (3+2√2)
by rationalizing it
= 1 / (3+2√2) × { (3-2√2)/ (3-2√2) }
= (3-2√2) / 9 - 8
= (3-2√2)
so,
1/x = (3-2√2)
the question is
{x -(1/x)}^2
{3 + 2√2 - ( 3 - 2 √2)}^2
( 3 -3 + 2√ 2 + 2√2)^2
( 4√2)^2
16 × 2
= 32.
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