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(√3-1)/(√3+1) = a + b√3
rationalizing the numerator and denominator
(√3-1)(√3-1)/(√3+1) (√3-1) = a+ b√3
=> a + b√3 = (√3+1)²/(3-1)
=> a + b√3 =( 3+1+2√3)/2
=> a + b√3 = (4+2√3)/2
=> a + b√3 = 2+√3
Comparing both sides, we have
a = 2
a = 2 b = 1
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