Question

please tell with explanation .....​

Answer 1

The answer is

a = 2 and b = -1

Answer 2

Answer:

$\frac{ \sqrt{3} \: - 1 }{ \sqrt{3 \: + 1} } = \frac{ \sqrt{3} \: - 1 }{ \sqrt{3 \: + 1} } \: \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1 }$

$\frac{( \sqrt{3} - 1) {}^{2} }{( \sqrt{3}) {}^{2} - (1) {}^{2} } = \: \frac{3 + 1 - 2 \sqrt{3} }{3 - 1}$

$\frac{4 - 2 \sqrt{3} }{2} = \: \frac{2(2 - \sqrt{3)} }{2} = \: 2 - \sqrt{3}$

so

2-√3. = a+b√3

2+(-1)√3 = a+b√3

a= 2

b= -1

hope it helps.....