Question

Please tell with full explanation T-T

Answer 1

Answer:

wretu

Step-by-step explanation:

Answer 2

In questions like these, first you simplify everything.

As we know, $(ab)^x = a^x * b^x$ and $a^x * a^y = a^{x+y}$

Using these two identities, we can simplify the values of all the numbers

I've done each one in two steps, the first step using the first identity and the second using the second :D

So, we can simplify $12^4, 9^3, 6^3$ and $8^2$ in the same way

$12^4 = 2^4 * 2^4 * 3^4$ = $2^8 * 3^4$

$9^3 = 3^3 * 3^3$ = $3^6$

$6^3 = 2^3 * 3^3$

$8^2 = 2^2 * 2^2 * 2^2$ = $2^6$

We can also simplify 4 and 27 as

$4 = 2^2$

$27 = 3^3$

Now, we can substitue all of this XD

$\frac{2^8 * 3^4 * 3^6 * 2^2}{2^3*3^3*2^6*3^3}$

Now, this looks complicated, but we can use the identity $a^x * a^y = a^{x+y}$ again.

Before I do that step let me rearrange it so it's easier to see XD

$\frac{2^8* 2^2 * 3^4 * 3^6 }{2^3*2^6*3^3*3^3}$

Alright, now watch closesly we're gonna use the identity to combine these.

$\frac{2^{8+2} * 3^{4+6} }{2^{3+6}*3^{3+3}}$

$\frac{2^{10} * 3^{10} }{2^{9}*3^6}$

Now, Last step we gotta simplify this further.

For this, we're gonna use the identity $\frac{a^x}{a^y} = a^{x-y}$

So, we have:

$2^{10-9} * 3^{10-6}$

$2^1 * 3^4$

$2* 81$

$162$

Hope this Helped!

Stay safe, stay hydrated and stay sanitized!

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(This took a very long time to type out, so I'd appreciate if you could mark it as brainliest (づ￣ 3￣)づ)