please telll me how the answer came .....Please tomorrow exam is there .
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here is your ans.
coef. of friction =1/root3
then force on block due to gravity are as shown in figure.
F=mgsin30=mg/2
N=mgcos30=mg*root(3)/2
then force due to friction=coeff.of frictio*N
=mg/2
since F=f
f=friction.
so block is in equillibrium.
so net force =0
acceleration=0
coef. of friction =1/root3
then force on block due to gravity are as shown in figure.
F=mgsin30=mg/2
N=mgcos30=mg*root(3)/2
then force due to friction=coeff.of frictio*N
=mg/2
since F=f
f=friction.
so block is in equillibrium.
so net force =0
acceleration=0
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mahendrachoudhary123:
that's is the problem. specially in western rajasthan like jaisalmer barmer jodhpur.but not jaipur
from where,you? in mahararashtra?
Mumbai kalyan
ok.
here the water is full but actual problem is that people waste water here
right. but i have heard that rain shortage is a problem for maharastra also.
ya it is right
here also water problem is there
ok byee
ok good night.
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hello i am sneha duplicate of you
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