Question

please
$\frac{ 2^{30} + 2^{29 } + 2 ^{28}}{?}$
evaluate​

Answer 1

Answer:

7/10

Step-by-step explanation:

$\: \frac{ {2}^{30 } + {2}^{29} + {2}^{28} \: }{ {2}^{31} + {2}^{30} - {2}^{29} }$

$\frac{ \: {2}^{28 + 2} + {2}^{28 + 1} + {2}^{28} }{ {2}^{29 + 2} + {2}^{29 + 1} - {2}^{29} }$

$taking \: common \: {2}^{28} in \: numerator \: and \: {2}^{29} in \: \\ denominator \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\frac{ {2}^{28} ( {2}^{2} + {2}^{1} + 1) }{ {2}^{29} ( {2}^{2} + {2}^{1} - 1 )}$

$\frac{1 \: (4 + 2 + 1)}{2 \: (4 + 2 - 1)}$

$\frac{1 \times 7}{2 \times 5}$

$\frac{7}{10}$