Question

please the right answer​

Answer 1

Answer and explanation:

Given,

OA = OB, OD = OC.

Therefore, in triangles AOD and BOC, we have

OA = OB (given)

Angle AOD = Angle BOC (vertically opposite angles are equal)

OD = OC.

Hence, by Side-Angle-Side congruence condition, triangle AOD is congruent to triangle BOC.

Hence, AD = BC (for they are congruent parta of congruent triangles)

Similarly, angle CBO = angle DAO.

But, AB acts as a transversal for BC and AD.

Hence, AD and BC are parallel to each other.

I hope this helps. :D

Answer 2

$\color{Teal}{❥Answer}$

Explanation

(i)△AOD और △BOC में,

OA = OB (दिया गया हैं)

OD = OC (दिया गया है)

ㄥAOD = ㄥBOC (शीर्षाभिमुख कोणों के युग्म)

इसलिए, △AOD= △BOC (भुजा-कोण-भुजा सर्वागसमता के नियम द्वारा)

(ii) ㄥOAD = ㄥOBC (CPCT)

और रेखाखंडों AD और BC के लिए एकान्तर कोणों के रूप में। इसलिए, AD || BC.

$\color{crimson}{❥English}$

In △AOD & △BCO

=> OD = OC (given)

OA = OB (given)

ㄥAOD = ㄥCOB (vertically opposite)

=> △AOD =△BOC

ㄥOAD = ㄥOBC (angles corresponding to congruent sides)

[∴AD & BC make equal angles with the same line AB]

Hence AD||BC

Hope it may help uh

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