Please this is urgent!!
An airplane accelerates down a runway at 3.20ms^-2 for 32.s unit finally lifts off the ground. Determine the distance traveled before
takeoff.
Please solve
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Answer:
Distance traveled = 1721.344m or ≈ 1.721 km
Explanation:
Answer starts from here
We know that where is the distance traveled, is constant acceleration experienced by an object, is its initial velocity and time of travel under this acceleration. Now we assume that the airplane starts from rest on the runway. Therefore, first term on the RHS is zero. Inserting given values in the equation = 12 × 3.20 × 32.82 = 1721.344m
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