Question

please this is urgent......

The size position of the metal is 10 ^ 10 N / m2. Its poise ratio is 0.20. If the average distance between the atoms is 3Å then the intermolecular force will be constant .....

A) 5.4 N/m

B) 7.5 N/m

C) 75 N/m

D) 30 N/m​

Answer 1

Answer:

A) 5.4 N/m ❌

B) 7.5 N/m ❌

C) 75 N/m. ✔️

D) 30 N/m ❌

Answer 2

Answer:

5.4 N/m

Explanation:

y=3k(1-2•)

=1.8×10¹⁰(1-2ו)

Inter atomic force constant is

K=1.8×10¹⁰×3×10‐¹⁰

=5.4N/m