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Let the 2 consecutive odd integers be
n and n+2.
n(n + 2) = 99
Solve for n.
n2 + 2n - 99 = 0
(n + 11)(n - 9) = 0 ⇒
Two solutions:
n = -11
n + 2 = -9
and
n = 9
n + 2 = 11
Test the answers.
OR
Let the two consecutive odd integers be x and x +2
x +2 Given :-
x(x+2) = 99
x² + 2x = 99
x² + 2x - 99 = 0
splitting the middle term :-
x² + 11x - 9x - 99 = 0
x( x + 11) - 9(x + 11) =0
(x - 9) ( x + 11) = 0
x = 9 , x = - 11
x = 9 is the value taken here :-
x = 9
x + 2 = 9 + 2 = 11
The no:s would be 9 and 11
Hope this helps....
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