Math, asked by abhi292967, 19 hours ago

please this question ​

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Answered by Anonymous
0

Answer:

its long answer you should give atleast 25 point to solve

Answered by fahai7122
1

Answer:

a =  {xy}^{p - 1}  \\ b =  {xy}^{q -  1}  \\ c =  {xy}^{r - 1}  \\  =   {a}^{q - r}  {b}^{r - p} {c}^{p - q}  \\  = ( {xy}^{p - 1})^{q - r} ({xy}^{q - 1} )({xy}^{r - 1} ) ^{p - q}  \\  =  {x}^{q - r + r - p + p - q} {y}^{qp + r - q - pr + qr  + p - qp - r + pr + q - p - qr}  \\  =  {x}^{0}  {y}^{0}  = 1

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