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by Pythagoras Theron
cinderella98:
could u pls send a pic of full solved sum
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HEY MATE !!!!!
Here is your answer...
Dimensions= a,b,c
Volume of cuboid = l×b×h
SO,
V = abc ---------(1)
NOW,
Surface area of cuboid = 2 (lb + bh + lh)
SO,
S = 2 ( ab + bc + ac) ---------(2)
Dividing (2) by (1)
S/V = 2 [ab + bc + ac] ÷ abc
S/V = [2ab + 2bc + 2ac] ÷ abc
S/V = [2ab ÷ abc] + [2bc ÷ abc] + [2ac ÷ abc]
S/V = [2/c + 2/a + 2/b]
TAKING 2 COMMON....
S/V = 2 [1/a +1/b + 1/c]
1/V = 2/S [1/a + 1/b + 1/c]
HOPE IT WILL HELP YOU....
PLZZ MARK IT AS BRAINLIEST...
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