Question

please this question its very important because tomorrow is my periodic test

Answer 1

Hello Friend ✌
Here is u r Ans ➡


✨
$( \sqrt{6} ) {}^{x - 2} = 1$


$using \: > x {}^{0} = 1$


$\sqrt{6} {}^{x - 2} = \sqrt{6} {}^{0}$

$x - 2 = 0$

$x = 2$
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