Question

please tommorow is my paper can anybody help me whose rank is genius and moderator​

Answer 1

Here observe that no of observations (n)=15

So median is

2

N+1

th

term

median =

2

15+1

th

term

=

2

16

th

term =8

th

term

median =20 __(2)

from (1) & (2)

mode = median

(Both are same)

Answer 2

$\large\boxed{\textsf{\textbf{\red{Answer \: of \: Question\: 1}}}}$

Arranging data in ascending order

• 5,9,10,12,15,16,19,20,20,20,23,24,25,25

Mode

• Mode is maximum occurring observation
• since 20 occurs 4 times
• Mode = 20

Median

• Number of observation = 15

since n is odd,

$Median = ( \frac{n + 1}{2} ) {}^{th} observation$

$= ( \frac{15 + 1}{2} ) {}^{th} = \frac{16}{2} {}^{th} = 8 {}^{th} \: observation$

$= 20$

so, both mode & median are 20

Hence, they are same

$\large\boxed{\textsf{\textbf{\red{Answer \: of \: Question\: 2}}}}$

Arranging data in ascending order

• 6,8,10,10,15,15,50,80,100,120

Mean

$Mean = \frac{6 + 8 + 10 + 10 + 15 + 15 + 15 + 50 + 80 + 100 + 120}{11}$

$= \frac{14 + 20 + 45 + 130 + 220}{11}$

$= \frac{429}{11} = 39$

Mode

• Mode = most occurring observation
• sincr 15 occurs 3 time
• mode = 15

Median

• Number of observation = 11

since n is odd,

$Median = ( \frac{n + 1)}{2} {}^{th} \: observation$

$= ( \frac{11 + 1}{2})^{th} = ( \frac{12}{2}) {}^{th} = 6 {}^{th} \: observation$

$= 15$

so,

• Mean = 39
• Mode = 15
• median = 15

there fore they are not same

$\large\boxed{\textsf{\textbf{\red{Answer \: of \: Question\: 3}}}}$

a) answer ☟︎︎

Mode

• Mode is maximum occurring observation
• since 38 & 43 both occurs 3 times
• both of them are mode
• Mode = 38,43

Median

• number of observation = 15

since n is odd,

$Median = ( \frac{n + 1}{2} ) {}^{th} \: observation$

$= ( \frac{15 + 1}{2} ) {}^{th} = (\frac{16}{2} )^{th} = 8 {}^{th} \: observation$

$= 40$

Median = 40

b) answer ☟︎︎︎

• yes there are 2 modes