Question

please try to find the area of polygon​

Answer 1

Answer:

PLS MARK ME AS THE BRAINLIEST

$8225units^{2}$

Step-by-step explanation:

Area of ΔAPB = $\frac{1}{2}bh$

⇒ $\frac{1}{2}$×AP×AB

⇒ $\frac{1}{2}$×$15$×$40$ $= 300$$units^{2}$

AR = AP + PQ + QR

⇒ AR = 15 + 50 + 25 = 90$units$

Area of ΔARF = $\frac{1}{2}bh$

⇒ $\frac{1}{2}$×AR×FR

⇒ $\frac{1}{2}$×$90$×$60$ $= 2700$$units^{2}$

ER = RS + SE

⇒ ER = 15 + 10 = 25$units$

Area of ΔERF = $\frac{1}{2}bh$

⇒ $\frac{1}{2}$×ER×RF

⇒ $\frac{1}{2}$×$25$×$60$ $= 750units^{2}$

Area of ΔSDE = $\frac{1}{2}bh$

⇒ $\frac{1}{2}$×SE×SD

⇒ $\frac{1}{2}$×$10$×$40$ $= 200units^{2}$

Area of trap(PBCQ) = $\frac{a+b}{2}h$

⇒ $\frac{PB+QC}{2}$×$PQ$

⇒ $\frac{40+55}{2}$×$50$ $= 2375units^{2}$

QS = QR + RS

⇒ QS = 25 + 15 = 40$units$

Area of trap(QCDS) = $\frac{a+b}{2}h$

⇒ $\frac{QC+SD}{2}$×$QS$

⇒ $\frac{55+40}{2}$×$40$ $= 1900units^{2}$

Area of the figure = $(300+2700+750+200+2375+1900)units^{2}$

⇒ $8225units^{2}$