Math, asked by varshithaammu23, 3 months ago

please try to find the area of polygon​

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Answered by shreeyasahoo123
1

Answer:

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8225units^{2}

Step-by-step explanation:

Area of ΔAPB = \frac{1}{2}bh

\frac{1}{2}×AP×AB

\frac{1}{2}×15×40 = 300units^{2}

AR = AP + PQ + QR

⇒ AR = 15 + 50 + 25 = 90units

Area of ΔARF = \frac{1}{2}bh

\frac{1}{2}×AR×FR

\frac{1}{2}×90×60 = 2700units^{2}

ER = RS + SE

⇒ ER = 15 + 10 = 25units

Area of ΔERF = \frac{1}{2}bh

\frac{1}{2}×ER×RF

\frac{1}{2}×25×60 = 750units^{2}

Area of ΔSDE = \frac{1}{2}bh

\frac{1}{2}×SE×SD

\frac{1}{2}×10×40 = 200units^{2}

Area of trap(PBCQ) = \frac{a+b}{2}h

\frac{PB+QC}{2}×PQ

\frac{40+55}{2}×50 = 2375units^{2}

QS = QR + RS

⇒ QS = 25 + 15 = 40units

Area of trap(QCDS) = \frac{a+b}{2}h

\frac{QC+SD}{2}×QS

\frac{55+40}{2}×40 = 1900units^{2}

Area of the figure = (300+2700+750+200+2375+1900)units^{2}

8225units^{2}

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